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    Glaciers found on Mars

    Red (Planet) Alert: Massive Subsurface Glaciers Discovered on Mars: Scientific American

    Another steps on the road to sending a manned mission to Mars? Hopefully!
    [img]http://img.photobucket.com/albums/v337/Igorod/troopdod.jpg[/img]
    [url=http://profile.xfire.com/trooper110][img]http://miniprofile.xfire.com/bg/co/type/1/trooper110.png[/img][/url]

    #2
    Wow, Earth 2 is here and has been here.

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      #3
      very cool

      I bet it's got some hardcore viruses to bring back!

      Comment


        #4
        Yeah, maybe THE virus
        [IMG]http://thepebkac.net/images/sigs/Outdoors_sig.jpg[/IMG]
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          #5
          Oh crap..hmm can you drink it to?
          [SIGPIC][/SIGPIC]

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            #6
            hmm....interesting.
            Hit 'em like comic books, kaboom! pow pow!

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              #7
              Gee- doesnt anyone ever think that this kind of claim is to insure they get funded?

              Related Question: anyone know what percentage the gravity of Mars is to the Earth?

              I know little Red is smaller than Earth, but I ask this because I look at the thrust and energy it takes to exit the gravitational pull of the Earth and I wonder how this will be possible without something extensive on Mars.

              Is it even feasible that 4-6 astronauts would be able to exit the Martian atmosphere?

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                #8
                There's very little Martian atmosphere to deal with when you look at exit velocities. Chances are that any mission would involve a ship built in Earth orbit, an actual space-faring ship really shouldn't be constructed in atmosphere, you can get better return for the materials if you build one that won't land, so they should be using a landing module of some kind. Also, I have to assume that they would be doing some kind of refueling on Mars, possible using water from the glaciers there, it would make the trip a lot less expensive in terms of mass and thrust ratios. And although Mars is close to being Earth-size, this does not mean equal gravitational fields, I *think* it's some kind of logarithmic equation to determine that.
                [img]http://img.photobucket.com/albums/v337/Igorod/troopdod.jpg[/img]
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